Because any translational motion problem can be separated into one or more 1-dimensional problems.
Problems are often analyzed this way - a complex problem can often be reduced to a set of simpler problems.
A scalar is something that has only a magnitude while a vector has both a magnitude and a direction. In 1-dimension it's hard to tell them apart!
Displacement is a vector representing the distance traveled and specifying the direction.
If you start at position xo and move to position x, your displacement Δx is defined as:
Δx = x - xo
If you move 5 meters north, Δx = 5 m north.
Now go the other direction, with a displacement of 3 m south.
The total distance traveled is 8 m. What is your net displacement?
Δx1 = +5 m north
Δx2 = +3 m south = - 3 m north
Net displacement: Δx = Δx1 + Δx2 = +5 -3 = +2 m north
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Velocity is the rate of change of position
Average velocity: vav | = |
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= |
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Instantaneous velocity: v | = |
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The instantaneous velocity is the slope of the line on a position-versus-time graph.
If the velocity is constant the instantaneous velocity is equal to the average velocity.
Turning the last equation around, the displacement can be found from:
Displacement: Δx | = | ∫ | v(t) dt |
Acceleration is the rate of change of velocity.
Average acceleration: aav | = |
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= |
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Instantaneous acceleration: a | = |
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The instantaneous acceleration is the slope of the line on a velocity-versus-time graph.
If the acceleration is constant the instantaneous acceleration is equal to the average acceleration.
Turning the last equation around:
Change in velocity: Δv | = | ∫ | a(t) dt |
These equations relate displacement, velocity, acceleration, and time, and apply under the following conditions:
v = vo + at
x = xo + vo t + ½ a t2
x = xo + ½ (v + vo) t
v2 = vo2 + 2 a (x - xo)
The equations are derived from the definitions of acceleration, velocity, and displacement.