Because any translational motion problem can be separated into one or more 1-dimensional problems.
Problems are often analyzed this way - a complex problem can often be reduced to a set of simpler problems.
A scalar is something that has only a magnitude while a vector has both a magnitude and a direction. In 1-dimension it's hard to tell them apart!
Displacement is a vector representing the distance traveled and specifying the direction.
If you start at position xo and move to position x, your displacement Δx is defined as:
Δx = x - xo
If you move 5 meters north, Δx = 5 m north.
Now go the other direction, with a displacement of 3 m south.
The total distance traveled is 8 m. What is your net displacement?
Δx1 = +5 m north
Δx2 = +3 m south = - 3 m north
Net displacement: Δx = Δx1 + Δx2 = +5 -3 = +2 m north
Instantaneous velocity: vx = dx/dt
Average velocity = vavg = Δx/Δt
Δx = ∫ vx dt
On your way to class one morning, you leave home and walk at 3 m/s east towards campus. After exactly one minute you realize that you've left your physics assignment at home, so you turn around and run, at 6 m/s, back to get it. You're running twice as fast as you walked, so it takes half as long (30 seconds) to get home again.
Note that you covered 180 m before turning around.
Analyzing the 90 second out-and-back trip, what is your average speed?
1. zero
2. 4 m/s
3. 4.5 m/s
4. 5 m/s
5. 9 m/s
Average speed is the total distance covered divided by the total time. That works out to 360 m / 90 s = 4 m/s
What is your average velocity?
1. zero
2. 1.5 m/s West
3. 3 m/s West
4. 4 m/s West
5. none of the above
Average velocity is the net displacement divided by the total time. Since the net displacement is zero, vavg = 0.
Instantaneous acceleration: ax = dv/dt
Average acceleration = aavg = Δv/Δt
Δvx = ∫ ax dt