Kinetic Theory: Connection between Energy and Pressure
Goal: Relate energy and pressure in an
ideal gas, and then derive E=3NkT/2.
Consider a cube of linear size L with N ideal gas molecules, each of mass
m.
The force exerted by one molecule when it collides with a wall of the box
that is perpendicular to the x-axis is:
F |
= |
2mvx
| |
Δt
|
|
The time between collisions with the right wall
is:
Δt | = |
2L
| |
vx
|
|
This gives the average force due to 1 molecule:
F |
= |
mvx2
| |
L
|
|
The total force on the wall is: F |
= |
Σ |
mvx2
| |
L
|
|
= |
mN
| |
L
|
|
Σ |
vx2
| |
N
|
|
≡ |
mN
| |
L |
|
〈vx2〉 |
Since all directions are equivalent:
〈v2〉=〈vx2 +
vy2 + vz2〉=
3〈vx2〉
we obtain: F |
= |
mN
| |
3L
|
|
〈v2〉 |
Dividing by the wall area, L2,
gives the pressure: P |
= |
mN
| |
3L3
|
|
〈v2〉 |
Equivalently: PV |
= |
N
| |
3
|
| m〈v2〉 |
= |
2N
| |
3
|
|
(½m〈v2〉) |
= |
2N
| |
3
|
|
ε |
&epsilon = energy per molecule