A Heat Pump
If you heat your home using electric heat, 1000 J of electrical energy can be transformed into 1000 J of heat. An alternate way of heating is to use a heat pump, which extracts heat from a lower-temperature region (outside the house) and transfers it to the higher-temperature region (inside the house). Let's say the work done in the process is 1000 J, and the temperatures are TH = 17°C = 290 K and TL = -23 °C = 250 K. What is the maximum amount of heat that can be transferred into the house?
- Something less than 1000 J (32/33) (97%)
- 1000 J (1/33) (3%)
- Something more than 1000 J (0/33) (0%)
The best we can do is determined by the Carnot relationship:
TL
| |
TH
|
|
= |
|QL|
| |
|QH|
|
|
Therefore: |QL| |
= |
TL
| |
TH
|
|
|QH| |
Using this in the energy equation gives:
|QH| = |QL| + W |
= |
TL
| |
TH
|
|
|QH| + W |
|QH| * |
( |
1 - |
TL
| |
TH
|
|
) |
= W |
|QH| |
= |
W TH
| |
TH - TL
|
|
For our numerical example this gives:
|QH| |
= |
1000 * 290
| |
290 - 250
|
|
= 1000 * 7.25 = 7250 J |
This is why heat pumps are much better than electric heaters. Instead of 1000 J of work going to 1000 J of heat we have 1000 J of work producing over 7000 J of heat.