Vertical circular motion

Common examples include:

We use DID TASC to analyze all these problems.

The Water Bucket

Step 1: Draw a diagram and coordinate system. Step 2: Isolate system.

Step 3: Draw all forces. Step 4: Take components.

At rest:

Crucial feature of uniform circular motion in the vertical plane:

Step 5: Apply Newton's second law.

At the bottom (y=up):   ΣFr = N - mg = mar = m v2/r      N = m v2/r + mg

At the top (y=down)      ΣFr = N + mg = mar = m v2/r      N = m v2/r - mg

Step 6: Solve. How slow can you go at the top and not fall off?

The limit is N =0! The corresponding speed is:  v2 = gr

Halfway up or down:   ΣFr = N = mar = m v2/r      N = m v2/r

At these points, mg provides the tangential acceleration that slows the object down (on the way up) or speeds it up (on the way down).


Car on a Hilly Road

What is the normal force on a car when it moves with speed v at the bottom of a circular valley of radius r?

  1. N = mg
  2. N = mv2/r
  3. N = mg + mv2/r
  4. N = mg - mv2/r
  5. N = mv2/r - mg

















At the bottom: N = mg +
m v2
r



What is the normal force on a car when it moves with speed v at the top of a circular hill of radius r?

  1. N = mg
  2. N = mv2/r
  3. N = mg + mv2/r
  4. N = mg - mv2/r
  5. N = mv2/r - mg

















At the top: N = mg -
m v2
r

The normal force equals your apparent weight. This is why you feel heavier at the bottom and lighter at the top.

A key difference between the car and water bucket examples: The normal is always up for the car. For the bucket, the normal force points from the bottom of the bucket toward the top of the bucket.