A ball on a 1.4-meter long string is being whirled in mid-air in a horizontal circle at a
constant speed v. The tension in the string is 100 N. The mass of the ball is 3.70 kg.
What is v?
As usual, begin with a free-body diagram.
Follow this up with an appropriate choice of coordinate system.
Let's go with a coordinate system with +x towards the center of the circle and +y vertically up.
The tension needs to be broken into components:
Tx = T cos(q)
Ty = T sin(q)
Apply Newton's Second Law in each direction:
|y direction|||||x direction|
|SFy = may = 0||||
|T sin(q) = mg||||
If we divide one equation by the other, we get a neat relationship for the angle of the string:
In this situation we still need to use the y-equation to find the angle. With T = 100 N and mg = 36.26 N, the angle works out to:
q = 21.26 degrees
Either the x-equation or the neat relationship we derived above will then get us the speed.
Be careful with r, which is NOT the length of the string.
r = 1.40 cos(q) = 1.305 m
This gives v = 5.73 m/s