A Heat Pump
If you heat your home using electric heat, 1000 J of electrical energy can be transformed into 1000 J of heat. An alternate way of heating is to use a heat pump, which extracts heat from a lower-temperature region (outside the house) and transfers it to the higher-temperature region (inside the house). Let's say the work done in the process is 1000 J, and the temperatures are Th = 17°C = 290 K and Tc = -23 °C = 250 K. What is the maximum amount of heat that can be transferred into the house?
- Something less than 1000 J
- 1000 J
- Something more than 1000 J
The best we can do is determined by the Carnot relationship:
| Tc
|  |
| Th
|
|
= |
| |Qc|
|  |
| |Qh|
|
|
| Therefore: |Qc| |
= |
| Tc
|  |
| Th
|
|
|Qh| |
Using this in the energy equation gives:
| |Qh| = |Qc| + W |
= |
| Tc
|  |
| Th
|
|
|Qh| + W |
| |Qh| * |
( |
1 - |
| Tc
|  |
| Th
|
|
) |
= W |
| |Qh| |
= |
| W Th
|  |
| Th - Tc
|
|
For our numerical example this gives:
| |Qh| |
= |
| 1000 * 290
|  |
| 290 - 250
|
|
= 1000 * 7.25 = 7250 J |
This is why heat pumps are much better than electric heaters. Instead of 1000 J of work going to 1000 J of heat we have 1000 J of work producing over 7000 J of heat.