Can we fill in anything else at this point or do we need to calculate something first?

1. We need to calculate something first
2. We know Q for the 2 to 3 process
3. We know Q for the 3 to 1 process
4. We know Q for the entire cycle
5. We know DE_int for the 1 to 2 process
6. We know DE_int for the 2 to 3 process
7. We know W for the 1 to 2 process
8. We know W for the 3 to 1 process

We can apply the First Law of Thermodynamics to the entire cycle. Because DE_int for an entire cycle is always zero, over an entire cycle we get Q = W, which in this case is -19400 J.

At this point we need to do a calculation of something. Without integrating or using logarithms, what could we calculate?

1. Q for the 2 to 3 process
2. Q for the 3 to 1 process
3. DE_int for either the 1 to 2 process or the 2 to 3 process
4. W for the 1 to 2 process
5. W for the 3 to 1 process

To find the work in the adiabatic 1 to 2 process would require an integral. To find the work, or the heat, in the isothermal 3 to 1 process would require logarithms.

We can find either of the two changes in internal energy, however. Finding the heat (Q) for the 2 to 3 process is also possible.

For the 2 to 3 process:

DE_int = n C_V DT

DE_int = (5/2) nR DT = 2.5*100*200 = 50000 J.

From there we can get to:

Which leads to:

Finally, we get the complete table: